The distance between the line and the point is:
$$ d = 2 $$The distance from the point $ (x_0, y_0) $ to the line $ Ax + By + C = 0 $ is given by:
$$ d = \frac{ \left| Ax_0 + B_yo + C \right| }{ \sqrt{A^2 + B^2}} $$After substituting: $ A = 12 $ , $ B = -5 $ , $ C = -4 $ , $ x_0 = -1 $ and $ y_0 = 2 $ we have:
$$ \begin{aligned} d =& \frac{ \left| 12\cdot\left(-1\right) +\left(-5\right)\cdot2 + \left( -4\right) \right| }{\sqrt{ 12^2 + (-5)^2}} = \\ d =& \frac{ \left| -12 -10 -4 \right| }{\sqrt{ 144 + 25}} = \\ d =& \frac{ \left| -26 \right| }{\sqrt{ 169}} = \\ d =& \frac{ 26 }{ 13 } = \\ d =& 2 \end{aligned} $$