The distance between the line and the point is:
$$ d = 7.3913 $$The distance from the point $ (x_0, y_0) $ to the line $ Ax + By + C = 0 $ is given by:
$$ d = \frac{ \left| Ax_0 + B_yo + C \right| }{ \sqrt{A^2 + B^2}} $$After substituting: $ A = 1 $ , $ B = 2.1175 $ , $ C = -16.249 $ , $ x_0 = 15.58 $ and $ y_0 = 8.49 $ we have:
$$ \begin{aligned} d =& \frac{ \left| 1\cdot15.58 +2.1175\cdot8.49 + \left( -16.249\right) \right| }{\sqrt{ 1^2 + 2.1175^2}} = \\ d =& \frac{ \left| 15.58 + 17.9777 -16.249 \right| }{\sqrt{ 1 + 4.4838}} = \\ d =& \frac{ \left| 17.3086 \right| }{\sqrt{ 5.4838}} = \\ d =& \frac{ 17.3086 }{ 2.3418 } = \\ d =& 7.3913 \end{aligned} $$