The distance between the line and the point is:
$$ d = \frac{ 56 }{ 13 } $$The distance from the point $ (x_0, y_0) $ to the line $ Ax + By + C = 0 $ is given by:
$$ d = \frac{ \left| Ax_0 + B_yo + C \right| }{ \sqrt{A^2 + B^2}} $$After substituting: $ A = 5 $ , $ B = 12 $ , $ C = 17 $ , $ x_0 = 3 $ and $ y_0 = 2 $ we have:
$$ \begin{aligned} d =& \frac{ \left| 5\cdot3 +12\cdot2 + 17 \right| }{\sqrt{ 5^2 + 12^2}} = \\ d =& \frac{ \left| 15 + 24 + 17 \right| }{\sqrt{ 25 + 144}} = \\ d =& \frac{ \left| 56 \right| }{\sqrt{ 169}} = \\ d =& \frac{ 56 }{ 13 } = \\ d =& \frac{ 56 }{ 13 } \end{aligned} $$