The distance between the line and the point is:
$$ d = 5 $$The distance from the point $ (x_0, y_0) $ to the line $ Ax + By + C = 0 $ is given by:
$$ d = \frac{ \left| Ax_0 + B_yo + C \right| }{ \sqrt{A^2 + B^2}} $$After substituting: $ A = 3 $ , $ B = 4 $ , $ C = 0 $ , $ x_0 = 3 $ and $ y_0 = 4 $ we have:
$$ \begin{aligned} d =& \frac{ \left| 3\cdot3 +4\cdot4 + 0 \right| }{\sqrt{ 3^2 + 4^2}} = \\ d =& \frac{ \left| 9 + 16 + 0 \right| }{\sqrt{ 9 + 16}} = \\ d =& \frac{ \left| 25 \right| }{\sqrt{ 25}} = \\ d =& \frac{ 25 }{ 5 } = \\ d =& 5 \end{aligned} $$