The distance between the line and the point is:
$$ d = \sqrt{ 73 } $$The distance from the point $ (x_0, y_0) $ to the line $ Ax + By + C = 0 $ is given by:
$$ d = \frac{ \left| Ax_0 + B_yo + C \right| }{ \sqrt{A^2 + B^2}} $$To apply this formula, we first need to express the line in standard form
$$\begin{aligned} y & = - \frac{ 3 }{ 8 } x + 8 \\8 \cdot y &= 8 \cdot \left( - \frac{ 3 }{ 8 } x + 8 \right) \\8 \cdot y &= - 3 x + 64 \\3x+8y-64&=0\end{aligned}$$After substituting: $ A = 3 $ , $ B = 8 $ , $ C = -64 $ , $ x_0 = 3 $ and $ y_0 = 16 $ we have:
$$ \begin{aligned} d =& \frac{ \left| 3\cdot3 +8\cdot16 + \left( -64\right) \right| }{\sqrt{ 3^2 + 8^2}} = \\ d =& \frac{ \left| 9 + 128 -64 \right| }{\sqrt{ 9 + 64}} = \\ d =& \frac{ \left| 73 \right| }{\sqrt{ 73}} = \\ d =& \frac{ 73 }{ \sqrt{ 73 } } = \\ d =& \sqrt{ 73 } \end{aligned} $$