The distance between the line and the point is:
$$ d = 2 $$The distance from the point $ (x_0, y_0) $ to the line $ Ax + By + C = 0 $ is given by:
$$ d = \frac{ \left| Ax_0 + B_yo + C \right| }{ \sqrt{A^2 + B^2}} $$To apply this formula, we first need to express the line in standard form
$$\begin{aligned} y & = - \frac{ 3 }{ 4 } x \\4 \cdot y &= 4 \cdot \left( - \frac{ 3 }{ 4 } x \right) \\4 \cdot y &= - 3 x \\3x+4y&=0\end{aligned}$$After substituting: $ A = 3 $ , $ B = 4 $ , $ C = 0 $ , $ x_0 = 2 $ and $ y_0 = 1 $ we have:
$$ \begin{aligned} d =& \frac{ \left| 3\cdot2 +4\cdot1 + 0 \right| }{\sqrt{ 3^2 + 4^2}} = \\ d =& \frac{ \left| 6 + 4 + 0 \right| }{\sqrt{ 9 + 16}} = \\ d =& \frac{ \left| 10 \right| }{\sqrt{ 25}} = \\ d =& \frac{ 10 }{ 5 } = \\ d =& 2 \end{aligned} $$