The distance between the line and the point is:
$$ d = \frac{ 4 \sqrt{ 5}}{ 5 } $$The distance from the point $ (x_0, y_0) $ to the line $ Ax + By + C = 0 $ is given by:
$$ d = \frac{ \left| Ax_0 + B_yo + C \right| }{ \sqrt{A^2 + B^2}} $$To apply this formula, we first need to express the line in standard form
$$\begin{aligned} y & = - 2 x \\2x+y&=0\end{aligned}$$After substituting: $ A = 2 $ , $ B = 1 $ , $ C = 0 $ , $ x_0 = -1 $ and $ y_0 = 6 $ we have:
$$ \begin{aligned} d =& \frac{ \left| 2\cdot\left(-1\right) +1\cdot6 + 0 \right| }{\sqrt{ 2^2 + 1^2}} = \\ d =& \frac{ \left| -2 + 6 + 0 \right| }{\sqrt{ 4 + 1}} = \\ d =& \frac{ \left| 4 \right| }{\sqrt{ 5}} = \\ d =& \frac{ 4 }{ \sqrt{ 5 } } = \\ d =& \frac{ 4 \sqrt{ 5}}{ 5 } \end{aligned} $$