The given linear equation is:
$$ \color{blue}{ x+3y = 2 } $$To find y - intercept we substitute $ \color{blue}{x = 0} $ into line equation.
$$\begin{aligned} x+3y &= 2 \\ \color{blue}{ 0 }+3y &= 2\\3y &= 2\\y &= \frac{ 2 }{ 3 } \end{aligned} $$So, the point $\left(0, \frac{ 2 }{ 3 } \right)$ is on the y axis.
To find x - intercept we substitute $\color{blue}{ y = 0 }$.
$$ \begin{aligned} x+3y &= 2 \\x+3\cdot \color{blue}{ 0 } &= 2\\x &= 2\\ x &= 2 \end{aligned} $$So, the point $ \left( 2 ,0 \right) $ is on the x axis.
The graph of the function is: