The given linear equation is:
$$ \color{blue}{ -2x+y = 3 } $$To find y - intercept we substitute $ \color{blue}{x = 0} $ into line equation.
$$\begin{aligned} -2x+y &= 3 \\ -2\cdot \color{blue}{ 0 }+y &= 3\\y &= 3\\y &= 3 \end{aligned} $$So, the point $\left(0, 3 \right)$ is on the y axis.
To find x - intercept we substitute $\color{blue}{ y = 0 }$.
$$ \begin{aligned} -2x+y &= 3 \\-2x+\color{blue}{ 0 } &= 3\\-2x &= 3\\ x &= -\frac{ 3 }{ 2 } \end{aligned} $$So, the point $ \left( -\frac{ 3 }{ 2 } ,0 \right) $ is on the x axis.
The graph of the function is: