The given equation is:
$$ \color{blue}{ y = \frac{ 1 }{ 3 } x + 2 } $$To draw the graph we will find y-intercept and x-intecept.
To find y - intercept we substitute $ \color{blue}{x = 0} $:
$$ \begin{aligned} y &= \frac{ 1 }{ 3 } x + 2 \\y &= \frac{ 1 }{ 3 } \cdot \color{blue}{0} + 2\\y &= 2 \\\end{aligned} $$To find x - intercept we substitute $ \color{blue}{y = 0}$:
$$ \begin{aligned} y &= \frac{ 1 }{ 3 } x + 2 \\\color{blue}{0} &= \frac{ 1 }{ 3 } x + 2\\x &= -6\end{aligned} $$So, the graph of the equation is: