Question
Answer
$$sqroot\cdot(-36)=-36o^2qrst$$
Explanation
| $$ \begin{aligned}sqroot\cdot(-36)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}-36o^2qrst\end{aligned} $$ | |
| ① | $$ s q r o o t \cdot -36 = -36 o^{1 + 1} q r s t = -36 o^2 q r s t $$ |
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