Question
Answer
$$arctan(-\dfrac{10}{-10r\cdot3})=-\dfrac{10a^2cnrt}{-30r}$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}arctan(-\frac{10}{-10r\cdot3})& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}a^2cnrt(-\frac{10}{-10r\cdot3}) \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}-\frac{10a^2cnrt}{-30r}\end{aligned} $$ | |
| ① | $$ a r c t a n = a^{1 + 1} c n r t = a^2 c n r t $$ |
| ② | Multiply $a^2cnrt$ by $ \dfrac{-10}{-30r} $ to get $ \dfrac{ -10a^2cnrt }{ -30r } $. Step 1: Write $ a^2cnrt $ as a fraction by putting $ \color{red}{1} $ in the denominator. Step 2: Multiply numerators and denominators. Step 3: Simplify numerator and denominator. $$ \begin{aligned} a^2cnrt \cdot \frac{-10}{-30r} & \xlongequal{\text{Step 1}} \frac{a^2cnrt}{\color{red}{1}} \cdot \frac{-10}{-30r} \xlongequal{\text{Step 2}} \frac{ a^2cnrt \cdot \left( -10 \right) }{ 1 \cdot \left( -30r \right) } = \\[1ex] & \xlongequal{\text{Step 3}} \frac{ -10a^2cnrt }{ -30r } \end{aligned} $$ |
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