Question
Answer
$$8\cdot\dfrac{i}{-1+3i}=\dfrac{-8i+24}{10}$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}8 \cdot \frac{i}{-1+3i}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}8 \cdot \frac{3-i}{10} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}\frac{-8i+24}{10}\end{aligned} $$ | |
| ① | Divide $ \, i \, $ by $ \, -1+3i \, $ to get $\,\, \dfrac{3-i}{10} $. ( view steps ) |
| ② | Multiply $8$ by $ \dfrac{3-i}{10} $ to get $ \dfrac{-8i+24}{10} $. Step 1: Write $ 8 $ as a fraction by putting $ \color{red}{1} $ in the denominator. Step 2: Multiply numerators and denominators. Step 3: Simplify numerator and denominator. $$ \begin{aligned} 8 \cdot \frac{3-i}{10} & \xlongequal{\text{Step 1}} \frac{8}{\color{red}{1}} \cdot \frac{3-i}{10} \xlongequal{\text{Step 2}} \frac{ 8 \cdot \left( 3-i \right) }{ 1 \cdot 10 } = \\[1ex] & \xlongequal{\text{Step 3}} \frac{ 24-8i }{ 10 } = \frac{-8i+24}{10} \end{aligned} $$ |
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