Question
Answer
$$8262.4\cdot\dfrac{j}{80+103.28j}=\dfrac{8262j}{103j+80}$$
Explanation
| $$ \begin{aligned}8262.4 \cdot \frac{j}{80+103.28j}& \xlongequal{ }8262.4 \cdot \frac{j}{80+103j} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{8262j}{103j+80}\end{aligned} $$ | |
| ① | Multiply $8262$ by $ \dfrac{j}{80+103j} $ to get $ \dfrac{8262j}{103j+80} $. Step 1: Write $ 8262 $ as a fraction by putting $ \color{red}{1} $ in the denominator. Step 2: Multiply numerators and denominators. Step 3: Simplify numerator and denominator. $$ \begin{aligned} 8262 \cdot \frac{j}{80+103j} & \xlongequal{\text{Step 1}} \frac{8262}{\color{red}{1}} \cdot \frac{j}{80+103j} \xlongequal{\text{Step 2}} \frac{ 8262 \cdot j }{ 1 \cdot \left( 80+103j \right) } = \\[1ex] & \xlongequal{\text{Step 3}} \frac{ 8262j }{ 80+103j } = \frac{8262j}{103j+80} \end{aligned} $$ |
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