Question
Answer
$$7-6i-2\cdot(2+3i)=-12i+3$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}7-6i-2\cdot(2+3i)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}7-6i-(4+6i) \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}7-6i-4-6i \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}-12i+3\end{aligned} $$ | |
| ① | Multiply $ \color{blue}{2} $ by $ \left( 2+3i\right) $ $$ \color{blue}{2} \cdot \left( 2+3i\right) = 4+6i $$ |
| ② | Remove the parentheses by changing the sign of each term within them. $$ - \left( 4+6i \right) = -4-6i $$ |
| ③ | Combine like terms: $$ \color{blue}{7} \color{red}{-6i} \color{blue}{-4} \color{red}{-6i} = \color{red}{-12i} + \color{blue}{3} $$ |
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