Question
Answer
$$6i\cdot(1-3i)=6i+18$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}6i\cdot(1-3i)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}6i-18i^2 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}6i+18\end{aligned} $$ | |
| ① | Multiply $ \color{blue}{6i} $ by $ \left( 1-3i\right) $ $$ \color{blue}{6i} \cdot \left( 1-3i\right) = 6i-18i^2 $$ |
| ② | $$ -18i^2 = -18 \cdot (-1) = 18 $$ |
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