Question
Answer
$$5\cdot\dfrac{i}{-10+5i}=\dfrac{-10i+5}{25}$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}5 \cdot \frac{i}{-10+5i}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}5 \cdot \frac{1-2i}{25} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}\frac{-10i+5}{25}\end{aligned} $$ | |
| ① | Divide $ \, i \, $ by $ \, -10+5i \, $ to get $\,\, \dfrac{1-2i}{25} $. ( view steps ) |
| ② | Multiply $5$ by $ \dfrac{1-2i}{25} $ to get $ \dfrac{-10i+5}{25} $. Step 1: Write $ 5 $ as a fraction by putting $ \color{red}{1} $ in the denominator. Step 2: Multiply numerators and denominators. Step 3: Simplify numerator and denominator. $$ \begin{aligned} 5 \cdot \frac{1-2i}{25} & \xlongequal{\text{Step 1}} \frac{5}{\color{red}{1}} \cdot \frac{1-2i}{25} \xlongequal{\text{Step 2}} \frac{ 5 \cdot \left( 1-2i \right) }{ 1 \cdot 25 } = \\[1ex] & \xlongequal{\text{Step 3}} \frac{ 5-10i }{ 25 } = \frac{-10i+5}{25} \end{aligned} $$ |
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