Question
Answer
$$3i\cdot(4-2i)=12i+6$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}3i\cdot(4-2i)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}12i-6i^2 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}12i+6\end{aligned} $$ | |
| ① | Multiply $ \color{blue}{3i} $ by $ \left( 4-2i\right) $ $$ \color{blue}{3i} \cdot \left( 4-2i\right) = 12i-6i^2 $$ |
| ② | $$ -6i^2 = -6 \cdot (-1) = 6 $$ |
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