Question
Answer
$$2i(3i^2+5i)=-6i-10$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}2i(3i^2+5i)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}2i\cdot(-3+5i) \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}-6i+10i^2 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}-6i-10\end{aligned} $$ | |
| ① | $$ 3i^2 = 3 \cdot (-1) = -3 $$ |
| ② | Multiply $ \color{blue}{2i} $ by $ \left( -3+5i\right) $ $$ \color{blue}{2i} \cdot \left( -3+5i\right) = -6i+10i^2 $$ |
| ③ | $$ 10i^2 = 10 \cdot (-1) = -10 $$ |
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