Question
Answer
$$2\cdot(-2+i)+3\cdot(7+4i)=14i+17$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}2\cdot(-2+i)+3\cdot(7+4i)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}-4+2i+21+12i \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}14i+17\end{aligned} $$ | |
| ① | Multiply $ \color{blue}{2} $ by $ \left( -2+i\right) $ $$ \color{blue}{2} \cdot \left( -2+i\right) = -4+2i $$Multiply $ \color{blue}{3} $ by $ \left( 7+4i\right) $ $$ \color{blue}{3} \cdot \left( 7+4i\right) = 21+12i $$ |
| ② | Combine like terms: $$ \color{blue}{-4} + \color{red}{2i} + \color{blue}{21} + \color{red}{12i} = \color{red}{14i} + \color{blue}{17} $$ |
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