Question
Answer
$$11i\cdot(-8+10i)=-88i-110$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}11i\cdot(-8+10i)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}-88i+110i^2 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}-88i-110\end{aligned} $$ | |
| ① | Multiply $ \color{blue}{11i} $ by $ \left( -8+10i\right) $ $$ \color{blue}{11i} \cdot \left( -8+10i\right) = -88i+110i^2 $$ |
| ② | $$ 110i^2 = 110 \cdot (-1) = -110 $$ |
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