Question
Answer
$$-8i\cdot(8+2i)=-64i+16$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}-8i\cdot(8+2i)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}-(64i+16i^2) \xlongequal{ } \\[1 em] & \xlongequal{ }-(64i-16) \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}-64i+16\end{aligned} $$ | |
| ① | Multiply $ \color{blue}{8i} $ by $ \left( 8+2i\right) $ $$ \color{blue}{8i} \cdot \left( 8+2i\right) = 64i+16i^2 $$ |
| ② | Remove the parentheses by changing the sign of each term within them. $$ - \left(64i-16 \right) = -64i+16 $$ |
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