Question
Answer
$$-(-2-6i)\cdot(-2+6i)=-40$$
Explanation
| $$ \begin{aligned}-(-2-6i)\cdot(-2+6i)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}-(4-12i+12i-36i^2) \xlongequal{ } \\[1 em] & \xlongequal{ }-(-36i^2+4) \xlongequal{ } \\[1 em] & \xlongequal{ }-(36+4) \xlongequal{ } \\[1 em] & \xlongequal{ }-40\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{-2-6i}\right) $ by each term in $ \left( -2+6i\right) $. $$ \left( \color{blue}{-2-6i}\right) \cdot \left( -2+6i\right) = 4 -\cancel{12i}+ \cancel{12i}-36i^2 $$ |
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