Question
Answer
$$(r-7)(r-14)=r^2-21r+98$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(r-7)(r-14)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}r^2-14r-7r+98 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}r^2-21r+98\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{r-7}\right) $ by each term in $ \left( r-14\right) $. $$ \left( \color{blue}{r-7}\right) \cdot \left( r-14\right) = r^2-14r-7r+98 $$ |
| ② | Combine like terms: $$ r^2 \color{blue}{-14r} \color{blue}{-7r} +98 = r^2 \color{blue}{-21r} +98 $$ |
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