Question
Answer
$$(m-5)(m^2+5m-6)=m^3-31m+30$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(m-5)(m^2+5m-6)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}m^3+5m^2-6m-5m^2-25m+30 \xlongequal{ } \\[1 em] & \xlongequal{ }m^3+ \cancel{5m^2}-6m -\cancel{5m^2}-25m+30 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}m^3-31m+30\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{m-5}\right) $ by each term in $ \left( m^2+5m-6\right) $. $$ \left( \color{blue}{m-5}\right) \cdot \left( m^2+5m-6\right) = m^3+ \cancel{5m^2}-6m -\cancel{5m^2}-25m+30 $$ |
| ② | Combine like terms: $$ m^3+ \, \color{blue}{ \cancel{5m^2}} \, \color{green}{-6m} \, \color{blue}{ -\cancel{5m^2}} \, \color{green}{-25m} +30 = m^3 \color{green}{-31m} +30 $$ |
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