Question
Answer
$$\dfrac{i^3-i}{i}=-2$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}\frac{i^3-i}{i}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{-i-i}{i} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}-\frac{2i}{i} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}-2\end{aligned} $$ | |
| ① | $$ i^3 = \color{blue}{i^2} \cdot i =
( \color{blue}{-1}) \cdot i =
- \, i $$ |
| ② | Simplify numerator $$ \color{blue}{-i} \color{blue}{-i} = \color{blue}{-2i} $$ |
| ③ | Divide $ \, -2i \, $ by $ \, i \, $ to get $\,\, -2 $. ( view steps ) |
This page was created using
Complex Expression calculator