Question
Answer
$$\dfrac{i(x-1)+x+1}{i(x-1)-x-1}=\dfrac{ix-i+x+1}{ix-i-x-1}$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}\frac{i(x-1)+x+1}{i(x-1)-x-1}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}\frac{ix-i+x+1}{ix-i-x-1}\end{aligned} $$ | |
| ① | Multiply $ \color{blue}{i} $ by $ \left( x-1\right) $ $$ \color{blue}{i} \cdot \left( x-1\right) = ix-i $$ |
| ② | Multiply $ \color{blue}{i} $ by $ \left( x-1\right) $ $$ \color{blue}{i} \cdot \left( x-1\right) = ix-i $$ |
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