Question
Answer
$$\dfrac{8+i}{-4-2i}=\dfrac{-17+6i}{10}$$
Explanation
| $$ \begin{aligned}\frac{8+i}{-4-2i}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{-17+6i}{10}\end{aligned} $$ | |
| ① | Divide $ \, 8+i \, $ by $ \, -4-2i \, $ to get $\,\, \dfrac{-17+6i}{10} $. ( view steps ) |
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