Question
Answer
$$(8-3i)\cdot(-2-3i)=9i^2-18i-16$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(8-3i)\cdot(-2-3i)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}-16-24i+6i+9i^2 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}9i^2-18i-16\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{8-3i}\right) $ by each term in $ \left( -2-3i\right) $. $$ \left( \color{blue}{8-3i}\right) \cdot \left( -2-3i\right) = -16-24i+6i+9i^2 $$ |
| ② | Combine like terms: $$ -16 \color{blue}{-24i} + \color{blue}{6i} +9i^2 = 9i^2 \color{blue}{-18i} -16 $$ |
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