Question
Answer
$$(8-11i)\cdot(8-11i)=121i^2-176i+64$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(8-11i)\cdot(8-11i)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}64-88i-88i+121i^2 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}121i^2-176i+64\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{8-11i}\right) $ by each term in $ \left( 8-11i\right) $. $$ \left( \color{blue}{8-11i}\right) \cdot \left( 8-11i\right) = 64-88i-88i+121i^2 $$ |
| ② | Combine like terms: $$ 64 \color{blue}{-88i} \color{blue}{-88i} +121i^2 = 121i^2 \color{blue}{-176i} +64 $$ |
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