Question
Answer
$$(7-4i)e^{7x+4ix}+(7+4i)e^{7x+4ix}=14e^{7x+4ix}$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(7-4i)e^{7x+4ix}+(7+4i)e^{7x+4ix}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}(7-4i+7+4i)e^{7x+4ix} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}14e^{7x+4ix}\end{aligned} $$ | |
| ① | Use the distributive property. |
| ② | Combine like terms: $$ \color{blue}{7} \, \color{red}{ -\cancel{4i}} \,+ \color{blue}{7} + \, \color{red}{ \cancel{4i}} \, = \color{blue}{14} $$ |
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