Question
Answer
$$(6z-i)^2=-12iz+36z^2-1$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(6z-i)^2& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}36z^2-12iz+i^2 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}36z^2-12iz+(-1) \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}-12iz+36z^2-1\end{aligned} $$ | |
| ① | Find $ \left(6z-i\right)^2 $ using formula. $$ (A - B)^2 = \color{blue}{A^2} - 2 \cdot A \cdot B + \color{red}{B^2} $$where $ A = \color{blue}{ 6z } $ and $ B = \color{red}{ i }$. $$ \begin{aligned}\left(6z-i\right)^2 = \color{blue}{\left( 6z \right)^2} -2 \cdot 6z \cdot i + \color{red}{i^2} = 36z^2-12iz+i^2\end{aligned} $$ |
| ② | $$ i^2 = -1 $$ |
| ③ | Combine like terms: $$ -12iz+36z^2-1 = -12iz+36z^2-1 $$ |
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