Question
Answer
$$6+8i-(4-3i)=11i+2$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}6+8i-(4-3i)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}6+8i-4+3i \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}11i+2\end{aligned} $$ | |
| ① | Remove the parentheses by changing the sign of each term within them. $$ - \left( 4-3i \right) = -4+3i $$ |
| ② | Combine like terms: $$ \color{blue}{6} + \color{red}{8i} \color{blue}{-4} + \color{red}{3i} = \color{red}{11i} + \color{blue}{2} $$ |
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