Question
Answer
$$(6+3i)\cdot(-9-8i)=-24i^2-75i-54$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(6+3i)\cdot(-9-8i)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}-54-48i-27i-24i^2 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}-24i^2-75i-54\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{6+3i}\right) $ by each term in $ \left( -9-8i\right) $. $$ \left( \color{blue}{6+3i}\right) \cdot \left( -9-8i\right) = -54-48i-27i-24i^2 $$ |
| ② | Combine like terms: $$ -54 \color{blue}{-48i} \color{blue}{-27i} -24i^2 = -24i^2 \color{blue}{-75i} -54 $$ |
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