Question
Answer
$$\dfrac{4+sqrt(4^2-4\cdot5)}{2}=\dfrac{4+sqrt\cdot(-4)}{2}$$
Explanation
| $$ \begin{aligned}\frac{4+sqrt(4^2-4\cdot5)}{2}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{4+sqrt\cdot(16-20)}{2} \xlongequal{ } \\[1 em] & \xlongequal{ }\frac{4+sqrt\cdot(-4)}{2}\end{aligned} $$ | |
| ① | $ 4 \cdot 5 = 20 $ |
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