Question
Answer
$$(3+i)\cdot(-4+6i)=6i^2+14i-12$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(3+i)\cdot(-4+6i)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}-12+18i-4i+6i^2 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}6i^2+14i-12\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{3+i}\right) $ by each term in $ \left( -4+6i\right) $. $$ \left( \color{blue}{3+i}\right) \cdot \left( -4+6i\right) = -12+18i-4i+6i^2 $$ |
| ② | Combine like terms: $$ -12+ \color{blue}{18i} \color{blue}{-4i} +6i^2 = 6i^2+ \color{blue}{14i} -12 $$ |
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