Question
Answer
$$(3+i)\cdot(-2+3i)=3i^2+7i-6$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(3+i)\cdot(-2+3i)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}-6+9i-2i+3i^2 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}3i^2+7i-6\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{3+i}\right) $ by each term in $ \left( -2+3i\right) $. $$ \left( \color{blue}{3+i}\right) \cdot \left( -2+3i\right) = -6+9i-2i+3i^2 $$ |
| ② | Combine like terms: $$ -6+ \color{blue}{9i} \color{blue}{-2i} +3i^2 = 3i^2+ \color{blue}{7i} -6 $$ |
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