Question
Answer
$$(3i-2)(3i-2)=9i^2-12i+4$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(3i-2)(3i-2)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}9i^2-6i-6i+4 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}9i^2-12i+4\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{3i-2}\right) $ by each term in $ \left( 3i-2\right) $. $$ \left( \color{blue}{3i-2}\right) \cdot \left( 3i-2\right) = 9i^2-6i-6i+4 $$ |
| ② | Combine like terms: $$ 9i^2 \color{blue}{-6i} \color{blue}{-6i} +4 = 9i^2 \color{blue}{-12i} +4 $$ |
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