Question
Answer
$$(3i-2)(i+1)-7=3i^2+i-9$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(3i-2)(i+1)-7& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}3i^2+3i-2i-2-7 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}3i^2+i-9\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{3i-2}\right) $ by each term in $ \left( i+1\right) $. $$ \left( \color{blue}{3i-2}\right) \cdot \left( i+1\right) = 3i^2+3i-2i-2 $$ |
| ② | Combine like terms: $$ 3i^2+ \color{blue}{3i} \color{blue}{-2i} \color{red}{-2} \color{red}{-7} = 3i^2+ \color{blue}{i} \color{red}{-9} $$ |
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