Question
Answer
$$(3i-2)(6i+4)=18i^2-8$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(3i-2)(6i+4)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}18i^2+12i-12i-8 \xlongequal{ } \\[1 em] & \xlongequal{ }18i^2+ \cancel{12i} -\cancel{12i}-8 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}18i^2-8\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{3i-2}\right) $ by each term in $ \left( 6i+4\right) $. $$ \left( \color{blue}{3i-2}\right) \cdot \left( 6i+4\right) = 18i^2+ \cancel{12i} -\cancel{12i}-8 $$ |
| ② | Combine like terms: $$ 18i^2+ \, \color{blue}{ \cancel{12i}} \, \, \color{blue}{ -\cancel{12i}} \,-8 = 18i^2-8 $$ |
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