Question
Answer
$$(3-i)(i-2)=-i^2+5i-6$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(3-i)(i-2)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}3i-6-i^2+2i \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}-i^2+5i-6\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{3-i}\right) $ by each term in $ \left( i-2\right) $. $$ \left( \color{blue}{3-i}\right) \cdot \left( i-2\right) = 3i-6-i^2+2i $$ |
| ② | Combine like terms: $$ \color{blue}{3i} -6-i^2+ \color{blue}{2i} = -i^2+ \color{blue}{5i} -6 $$ |
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