Question
Answer
$$(3-5i)\cdot(2+2i)=-10i^2-4i+6$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(3-5i)\cdot(2+2i)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}6+6i-10i-10i^2 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}-10i^2-4i+6\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{3-5i}\right) $ by each term in $ \left( 2+2i\right) $. $$ \left( \color{blue}{3-5i}\right) \cdot \left( 2+2i\right) = 6+6i-10i-10i^2 $$ |
| ② | Combine like terms: $$ 6+ \color{blue}{6i} \color{blue}{-10i} -10i^2 = -10i^2 \color{blue}{-4i} +6 $$ |
This page was created using
Complex Expression calculator