Question
Answer
$$3-2isqrt\cdot3-(6+3isqrt\cdot3)-7i=-15iqrst-7i-3$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}3-2isqrt\cdot3-(6+3isqrt\cdot3)-7i& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}3-6iqrst-(6+9iqrst)-7i \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}3-6iqrst-6-9iqrst-7i \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}-15iqrst-7i-3\end{aligned} $$ | |
| ① | $$ 2 i s q r t \cdot 3 = 6 i q r s t $$$$ 3 i s q r t \cdot 3 = 9 i q r s t $$ |
| ② | Remove the parentheses by changing the sign of each term within them. $$ - \left( 6+9iqrst \right) = -6-9iqrst $$ |
| ③ | Combine like terms: $$ \color{blue}{3} \color{red}{-6iqrst} \color{blue}{-6} \color{red}{-9iqrst} -7i = \color{red}{-15iqrst} -7i \color{blue}{-3} $$ |
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