Question
Answer
$$3-2i+4\cdot(4+3i)=10i+19$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}3-2i+4\cdot(4+3i)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}3-2i+16+12i \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}10i+19\end{aligned} $$ | |
| ① | Multiply $ \color{blue}{4} $ by $ \left( 4+3i\right) $ $$ \color{blue}{4} \cdot \left( 4+3i\right) = 16+12i $$ |
| ② | Combine like terms: $$ \color{blue}{3} \color{red}{-2i} + \color{blue}{16} + \color{red}{12i} = \color{red}{10i} + \color{blue}{19} $$ |
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