Question
Answer
$$(3-2i)(i-4)=-2i^2+11i-12$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(3-2i)(i-4)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}3i-12-2i^2+8i \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}-2i^2+11i-12\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{3-2i}\right) $ by each term in $ \left( i-4\right) $. $$ \left( \color{blue}{3-2i}\right) \cdot \left( i-4\right) = 3i-12-2i^2+8i $$ |
| ② | Combine like terms: $$ \color{blue}{3i} -12-2i^2+ \color{blue}{8i} = -2i^2+ \color{blue}{11i} -12 $$ |
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