Question
Answer
$$(3-7i)\cdot(2-5i)=35i^2-29i+6$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(3-7i)\cdot(2-5i)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}6-15i-14i+35i^2 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}35i^2-29i+6\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{3-7i}\right) $ by each term in $ \left( 2-5i\right) $. $$ \left( \color{blue}{3-7i}\right) \cdot \left( 2-5i\right) = 6-15i-14i+35i^2 $$ |
| ② | Combine like terms: $$ 6 \color{blue}{-15i} \color{blue}{-14i} +35i^2 = 35i^2 \color{blue}{-29i} +6 $$ |
This page was created using
Complex Expression calculator