Question
Answer
$$(2+3i)\cdot(5+4i)=12i^2+23i+10$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(2+3i)\cdot(5+4i)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}10+8i+15i+12i^2 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}12i^2+23i+10\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{2+3i}\right) $ by each term in $ \left( 5+4i\right) $. $$ \left( \color{blue}{2+3i}\right) \cdot \left( 5+4i\right) = 10+8i+15i+12i^2 $$ |
| ② | Combine like terms: $$ 10+ \color{blue}{8i} + \color{blue}{15i} +12i^2 = 12i^2+ \color{blue}{23i} +10 $$ |
This page was created using
Complex Expression calculator