Question
Answer
$$(2+3i)\cdot(3-4i)=-12i^2+i+6$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(2+3i)\cdot(3-4i)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}6-8i+9i-12i^2 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}-12i^2+i+6\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{2+3i}\right) $ by each term in $ \left( 3-4i\right) $. $$ \left( \color{blue}{2+3i}\right) \cdot \left( 3-4i\right) = 6-8i+9i-12i^2 $$ |
| ② | Combine like terms: $$ 6 \color{blue}{-8i} + \color{blue}{9i} -12i^2 = -12i^2+ \color{blue}{i} +6 $$ |
This page was created using
Complex Expression calculator