Question
Answer
$$(2i\cdot(7-i))^{1/2}=(14i+2)^{1/2}$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(2i\cdot(7-i))^{1/2}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}(14i-2i^2)^{1/2} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}(14i+2)^{1/2}\end{aligned} $$ | |
| ① | Multiply $ \color{blue}{2i} $ by $ \left( 7-i\right) $ $$ \color{blue}{2i} \cdot \left( 7-i\right) = 14i-2i^2 $$ |
| ② | $$ -2i^2 = -2 \cdot (-1) = 2 $$ |
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