Question
Answer
$$\dfrac{25y^2-36}{25y^2-60y+36}=\dfrac{5y+6}{5y-6}$$
Explanation
| $$ \begin{aligned}\frac{25y^2-36}{25y^2-60y+36}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{5y+6}{5y-6}\end{aligned} $$ | |
| ① | Simplify $ \dfrac{25y^2-36}{25y^2-60y+36} $ to $ \dfrac{5y+6}{5y-6} $. Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{5y-6}$. $$ \begin{aligned} \frac{25y^2-36}{25y^2-60y+36} & =\frac{ \left( 5y+6 \right) \cdot \color{blue}{ \left( 5y-6 \right) }}{ \left( 5y-6 \right) \cdot \color{blue}{ \left( 5y-6 \right) }} = \\[1ex] &= \frac{5y+6}{5y-6} \end{aligned} $$ |
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